SOLUTION: my problem is 3acube-26a=9 what i did was moved the 9 over to the left and set equal to zero so now I have 3acubed-26a-9=0 now x=26+- the square root of(-26)cubed-4(3)(-9) all over
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-> SOLUTION: my problem is 3acube-26a=9 what i did was moved the 9 over to the left and set equal to zero so now I have 3acubed-26a-9=0 now x=26+- the square root of(-26)cubed-4(3)(-9) all over
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Question 598538: my problem is 3acube-26a=9 what i did was moved the 9 over to the left and set equal to zero so now I have 3acubed-26a-9=0 now x=26+- the square root of(-26)cubed-4(3)(-9) all over 2(3) came up with x=26+-28/6 this isnt the right answer it's says I must have two answer please help understand
You can put this solution on YOUR website! First, you do not have a quadratic equation!
What you have posted is: This is a cubic equation and, as such, will have three roots.
The roots are:
(