SOLUTION: I need your help onthe following problem: "A rectangle whose perimeter is 250 is 8 feet shorter than it is wide.Find the dimensions and area." Can you please help me.
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Question 56989: I need your help onthe following problem: "A rectangle whose perimeter is 250 is 8 feet shorter than it is wide.Find the dimensions and area." Can you please help me. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A rectangle whose perimeter is 250 is 8 feet shorter than it is wide.Find the dimensions and area." Can you please help me.
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It says: 2L + 2W = 250
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It also says: L = W - 8
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Sustitute (W-8) for L in the perimeter equation:
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2(W-8) + 2W = 250
2W - 16 + 2W = 250
4W = 250 + 16
4W = 266
W = 266/4
W = 66.5 ft is the width
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L = 66.5 - 8 = 58.5 ft is the length
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Check our solutions in the perimeter equation:
2(58.5) + 2(66.5) =
117 + 133 = 250
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Find the area: 58.5 * 66.5 = 3890.25 sq ft
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Make sense to you??
