SOLUTION: A catapult launches a boulder with an upward velocity of 148 ft/s. The height of the boulder (h) in feet after t seconds is given by the function h = –16t˛ + 148t + 30. How long do
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-> SOLUTION: A catapult launches a boulder with an upward velocity of 148 ft/s. The height of the boulder (h) in feet after t seconds is given by the function h = –16t˛ + 148t + 30. How long do
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Question 556451: A catapult launches a boulder with an upward velocity of 148 ft/s. The height of the boulder (h) in feet after t seconds is given by the function h = –16t˛ + 148t + 30. How long does it take the boulder to reach its maximum height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! A catapult launches a boulder with an upward velocity of 148 ft/s. The height of the boulder (h) in feet after t seconds is given by the function h = –16t˛ + 148t + 30.
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How long does it take the boulder to reach its maximum height?
max height reached at vertex
t = -b/(2a)
t = -148/(2*(-16))
t = -148/(-32)
t = 4.625 seconds
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What is the boulder’s maximum height? Round to the nearest hundredth, if necessary
set t to 4.625 and solve for h: feet
