SOLUTION: How can i find the vertex of Y=(x-4)^2 +5
Quadratic Equations and Parabolas
-> SOLUTION: How can i find the vertex of Y=(x-4)^2 +5
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How can i find the vertex of
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The vertex of y = a(x-h)^2+k is (h,k). In the case of y=(x-4)^2+5, we see that h=4 and k=5. So the vertex is (4,5)
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