SOLUTION: The position of an object moving in a straight line is given by s=t^2-8t, where s is in feet and t is the time in seconds the object has been in motion. How long (to the nearest t

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: The position of an object moving in a straight line is given by s=t^2-8t, where s is in feet and t is the time in seconds the object has been in motion. How long (to the nearest t      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 55366: The position of an object moving in a straight line is given by s=t^2-8t, where s is in feet and t is the time in seconds the object has been in motion. How long (to the nearest tenth) will it take the object to move 10 feet?
Answer by stanbon(48546) About Me  (Show Source):
You can put this solution on YOUR website!
s=t^2-8t
10=t^2-8t
t^2-8t-10=0
Use the quadratic formula to get:
t=[8+-sqrt(64+40)]/2
t=[8+-2sqrt(26)]]2
t=[4+-sqrt26]
t= 9.09 seconds
Cheers,
Stan H.