SOLUTION: 2. The perimeter of a rectangular field is 140 yards. The land sells for $10 / yd2 and the total cost of the land is $12,000. What are the dimensions of the field?

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: 2. The perimeter of a rectangular field is 140 yards. The land sells for $10 / yd2 and the total cost of the land is $12,000. What are the dimensions of the field?       Log On


   



Question 553299: 2. The perimeter of a rectangular field is 140 yards. The land sells for $10 / yd2 and the total cost of the land is $12,000. What are the dimensions of the field?

Answer by prateekagrawal(56) About Me  (Show Source):
You can put this solution on YOUR website!
Here area= cost/rate
so,
.
area=+12000%2F10+=+1200+yd%5E2+
is the area.
perimeter is 140 yards.
so, 2(l+b) = 140
l+b= 70
b= 70- l ----(1)
.
area = l*b =l*(70-l)=1200
solve this, we will get l=40 yd or 30 yd.
when l= 40yd, b= 30yd
and when l=30yd , b= 40 yd.
.
so, dimensions are 40yd x 30 yd.