SOLUTION: How do you derive the formula 1/2(n^2-n+2 using an^2+bn+c?

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: How do you derive the formula 1/2(n^2-n+2 using an^2+bn+c?       Log On


   



Question 530298: How do you derive the formula 1/2(n^2-n+2 using an^2+bn+c?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How do you derive the formula 1/2(n^2-n+2) using an^2+bn+c?
------------
(1/2)n^2 - (1/2)n + 1
---
n = [(1/2) +- sqrt((1/4)-4*(1/2)*1)]/1
----
etc.
Cheers,
Stan H.
=====