SOLUTION: -4x2+8x+3=0

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Question 530293: -4x2+8x+3=0
Answer by stanbon(57290) About Me  (Show Source):
You can put this solution on YOUR website!
-4x2+8x+3=0
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4x^2 - 8x -3 = 0
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x = [8 +- sqrt(64 - 4*4*-3)]/8
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x = [8 +- sqrt(112)]/8
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x = [8 +- sqrt(16*3)]/8
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x = 1 +- (1/2)sqrt(3)
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Cheers,
Stan H.
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