SOLUTION: how would you go about solving x^2-6x+9=100 useing square roots?

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 Question 523978: how would you go about solving x^2-6x+9=100 useing square roots?Answer by Edwin McCravy(8882)   (Show Source): You can put this solution on YOUR website!``` x² - 6x + 9 = 100 Factor the left side: (x-3)(x-3) = 100 Since the two factors are the same we can write the factor just once with a 2 exponent, that is, as a square of a binomial: (x-3)² = 100 Now we use the principle of square roots. x-3 = ± x-3 = ±10 Add 3 to both sides x = ±10 + 3 Then we make two equations, one using + and one using - x = 10 + 3, x = -10 + 3 x = 13, x = -7 Edwin```