SOLUTION: I am lost here, can someone help me? Find the x-intercepts y=x^2-4x+4

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: I am lost here, can someone help me? Find the x-intercepts y=x^2-4x+4      Log On


   

Question 52345This question is from textbook Beginnning Algebra
: I am lost here, can someone help me?

Find the x-intercepts
y=x^2-4x+4 This question is from textbook Beginnning Algebra

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
You find x intercepts by letting y=0 and solving for x. For this one let y=0, factor, then set each parenthese =0 and solve for x.
y=x^2-4x+4
0=(x-2)(x-2)
0=x-2
0+2=x-2+2
2=x
Since this is a perfect square trinomial, there is only one x-intercept.