SOLUTION: I need some help in finding the x -intercepts of y= x^2-x-3. I am using b sqrt -b^2-4ac/2a but am messing up somewhere if anyone can assist.

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: I need some help in finding the x -intercepts of y= x^2-x-3. I am using b sqrt -b^2-4ac/2a but am messing up somewhere if anyone can assist.      Log On

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Question 50797This question is from textbook
: I need some help in finding the x -intercepts of y= x^2-x-3. I am using b sqrt -b^2-4ac/2a but am messing up somewhere if anyone can assist.This question is from textbook

Answer by Earlsdon(6287) About Me  (Show Source):
You can put this solution on YOUR website!
Find the x-intercepts of:
y+=+x%5E2+-+x+-+3 The x-intercepts are found by setting y = 0.
x%5E2+-+x+-+3+=+0 Solve using the quadratic formula: x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a Here: a = 1, b = -1, c = -3
x+=+%28-%28-1%29%2B-sqrt%28%28-1%29%5E2+-+4%281%29%28-3%29%29%29%2F2%281%29 Simplify.
x+=+%281%2B-sqrt%281-%28-12%29%29%29%2F2
x+=+%281%2B-sqrt%2813%29%29%2F2
x+=+2.30277
x+=+-1.30277