SOLUTION: Please help me solve 16xsquared-8x-3=0

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Question 503218: Please help me solve 16xsquared-8x-3=0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

16x%5E2-8x-3=0 Start with the given equation.


Notice that the quadratic 16x%5E2-8x-3 is in the form of Ax%5E2%2BBx%2BC where A=16, B=-8, and C=-3


Let's use the quadratic formula to solve for "x":


x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29 Start with the quadratic formula


x+=+%28-%28-8%29+%2B-+sqrt%28+%28-8%29%5E2-4%2816%29%28-3%29+%29%29%2F%282%2816%29%29 Plug in A=16, B=-8, and C=-3


x+=+%288+%2B-+sqrt%28+%28-8%29%5E2-4%2816%29%28-3%29+%29%29%2F%282%2816%29%29 Negate -8 to get 8.


x+=+%288+%2B-+sqrt%28+64-4%2816%29%28-3%29+%29%29%2F%282%2816%29%29 Square -8 to get 64.


x+=+%288+%2B-+sqrt%28+64--192+%29%29%2F%282%2816%29%29 Multiply 4%2816%29%28-3%29 to get -192


x+=+%288+%2B-+sqrt%28+64%2B192+%29%29%2F%282%2816%29%29 Rewrite sqrt%2864--192%29 as sqrt%2864%2B192%29


x+=+%288+%2B-+sqrt%28+256+%29%29%2F%282%2816%29%29 Add 64 to 192 to get 256


x+=+%288+%2B-+sqrt%28+256+%29%29%2F%2832%29 Multiply 2 and 16 to get 32.


x+=+%288+%2B-+16%29%2F%2832%29 Take the square root of 256 to get 16.


x+=+%288+%2B+16%29%2F%2832%29 or x+=+%288+-+16%29%2F%2832%29 Break up the expression.


x+=+%2824%29%2F%2832%29 or x+=++%28-8%29%2F%2832%29 Combine like terms.


x+=+3%2F4 or x+=+-1%2F4 Simplify.


So the solutions are x+=+3%2F4 or x+=+-1%2F4

If you need more help, feel free to email me at jim_thompson5910@hotmail.com

Thanks,

Jim