SOLUTION: use the discriminant to determine the number of solutions and whether they are real or complex.
x^2 + 6x - 7 = 0
z^2 + z + 1 = 0
(3)^1/2 y^2 - 4y - 7(3)^1/2 = 0
I can not f
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: use the discriminant to determine the number of solutions and whether they are real or complex.
x^2 + 6x - 7 = 0
z^2 + z + 1 = 0
(3)^1/2 y^2 - 4y - 7(3)^1/2 = 0
I can not f
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Question 498924: use the discriminant to determine the number of solutions and whether they are real or complex.
x^2 + 6x - 7 = 0
z^2 + z + 1 = 0
(3)^1/2 y^2 - 4y - 7(3)^1/2 = 0
I can not figure these three out. Please help! Thanks
Suzie Answer by chessace(471) (Show Source):
You can put this solution on YOUR website! Discriminate of ax^2 + bx + c is sqrt(b^2-4ac)
6^2+4*7*1>0 so 2 real roots
1^2-4*1*1<0 so 2 complex roots
16-4(3^1/2)(-7*(3^1/2))=16+4*7*3>0 so 2 real roots
