SOLUTION: x square divided by (x-2)(x-3)=2 divided by (x-2)+ 6 divided by (x-2)(x-3). solve for x.

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Question 49727This question is from textbook
: x square divided by (x-2)(x-3)=2 divided by (x-2)+ 6 divided by (x-2)(x-3). solve for x. This question is from textbook

Answer by gsmani_iyer(201) About Me  (Show Source):
You can put this solution on YOUR website!

x%5E2%2F%28%28x-2%29%28x-3%29%29++=++%282%2F%28x-2%29%29%2B%286%2F%28x-2%29%28x-3%29%29

x%5E2%2F%28%28x-2%29%28x-3%29%29 = %282%28x-3%29%2B6%29%2F%28%28x-2%29%28x-3%29%29

As both the denominators are same,
x%5E2+=+2x-6%2B6. So, x%5E2+=+2x

x%5E2-2x+=+0. x%28x-2%29+=+0

So either x or (x-2) = 0.

Solution Set = {0, 2} Answer.