SOLUTION: Give exact and approximate solutions to three decimal places:
y^2-2y+1=100
If I follow the example in the book, I get the wrong answer. I am confused as how to work this prob
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: Give exact and approximate solutions to three decimal places:
y^2-2y+1=100
If I follow the example in the book, I get the wrong answer. I am confused as how to work this prob
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Question 486294: Give exact and approximate solutions to three decimal places:
y^2-2y+1=100
If I follow the example in the book, I get the wrong answer. I am confused as how to work this problem. Thank you for any help you are able to give. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Give exact and approximate solutions to three decimal places:
y^2-2y+1=100.
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To find the zeros you can either factor or use the quadradic formula.
Factoring: set expression = zero, use trial and error method, then check using FOIL.
y^2-2y-99=0
..
Quadratic formula: For given equation, a=1, b=-2, and c=-99
ans:
y=-9 or 11
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