Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: Can someone please help me with these? Please? Give exact and approximate solutions to three decimal places. x^2-7x+9=0 x^2+8x+16=49 (x-8)^2=81      Log On

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Give exact and approximate solutions to three decimal places.
x^2-7x+9=0
x^2+8x+16=49
(x-8)^2=81

You can put this solution on YOUR website!
x2-7x+9=0
 Solved by pluggable solver: SOLVE quadratic equation with variable Quadratic equation (in our case ) has the following solutons: For these solutions to exist, the discriminant should not be a negative number. First, we need to compute the discriminant : . Discriminant d=13 is greater than zero. That means that there are two solutions: . Quadratic expression can be factored: Again, the answer is: 5.30277563773199, 1.69722436226801. Here's your graph:

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x2+8x+16=49
x2+8x-33=0
(x+11)(x-3)
x=-11 or 3
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(x-8)2=81
x2-16x+64=81
x2-16x-17=0
(x+1)(x-17)=0
x=-1 or 17..