Question 464378: Hello, can you help me find the solutions to this question? Thank you in advance.
Find the vertex, the line of symmetry, the maximum or minimum of the quadratic function, and graph the function:
f(x)=-2x^2+2x+8
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find the vertex, the line of symmetry, the maximum or minimum of the quadratic function, and graph the function:
f(x)=-2x^2+2x+8
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standard form for parabola: y=(x-h)^2+k, (h,k) being the (x,y) coordinates of the vertex.
for given equation:
y=-2x^2+2x+8
completing the square
y=-2(x^2-x+1/4)+8+1/2
y=-(x-1/2)^2+17/2
This is a parabola that opens downward, with vertex at (1/2,17/2).
Axis of symmetry: x=1/2, maximum=17/2
See graph below as a visual check on answers:
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