SOLUTION: The area of this rectangle is 45 square units. Find its length (the horizontal side) and the width (the verticle side). Length is x+6, width is x-6 a) Write an equation using th

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: The area of this rectangle is 45 square units. Find its length (the horizontal side) and the width (the verticle side). Length is x+6, width is x-6 a) Write an equation using th      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 463347: The area of this rectangle is 45 square units. Find its length (the horizontal side) and the width (the verticle side). Length is x+6, width is x-6
a) Write an equation using the formula and the given information.
45=
b) Solve the equation, giving only the solution(s) that make sense in the problem. The solution for x is_____
c) Use the solution to find the indicated dimensions of the figure.
Length=
Width=
Answer by lwsshak3(6505) About Me  (Show Source):
You can put this solution on YOUR website!
The area of this rectangle is 45 square units. Find its length (the horizontal side) and the width (the verticle side). Length is x+6, width is x-6
a) Write an equation using the formula and the given information.
45=
b) Solve the equation, giving only the solution(s) that make sense in the problem. The solution for x is_____
c) Use the solution to find the indicated dimensions of the figure.
Length=
Width=
...
Given:
length=(x+6)
width=(x-6)
Area=45 sq units
..
Equation:
a) Area=length * width=(x+6)(x-6)=(x^2-36) (difference of two squares)
45=x^2-36
x^2=45+36=81
...
Solution:
b)x=±√81=±9
x=9
or
x=-9 (reject, dimension>0)
..
Dimensions:
c) length=x+6=9+6=15 units
width=x-6=9-6=3 units