SOLUTION: find the vertex, line of symmetry, and maximum or minimum value of the quadratic function: f(x)= -2x^2 + 2x + 10

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: find the vertex, line of symmetry, and maximum or minimum value of the quadratic function: f(x)= -2x^2 + 2x + 10      Log On


   

Question 458254: find the vertex, line of symmetry, and maximum or minimum value of the quadratic function: f(x)= -2x^2 + 2x + 10
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Given the quadratic function



The -coordinate of the vertex is:



The -coordinate of the vertex is:



The axis of symmetry is



The lead coefficient is negative, hence the parabola opens downward, hence the vertex is a maximum, and the maximum value is the value of the function (read -coordinate) at the vertex.

John

My calculator said it, I believe it, that settles it
The Out Campaign: Scarlet Letter of Atheism