SOLUTION: Determoine the domain and sketch the graph of the reducible function. f(x) = (x^2 - 25) / (2x - 10). f(x) = (x+2) / (x^2-x-6). when I did, the instructor said i was wrong; see

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Determoine the domain and sketch the graph of the reducible function. f(x) = (x^2 - 25) / (2x - 10). f(x) = (x+2) / (x^2-x-6). when I did, the instructor said i was wrong; see      Log On


   

Question 443134: Determoine the domain and sketch the graph of the reducible function.
f(x) = (x^2 - 25) / (2x - 10).
f(x) = (x+2) / (x^2-x-6).
when I did, the instructor said i was wrong; see his response:
what did i do wrong
The answer to #22, #26 are not correct as you submitted, since in a reducible function, the domain is determined based on the original function, not the reduced form! Please correct and submit.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Determine the domain and sketch the graph of the reducible function.
f(x) = (x^2 - 25) / (2x - 10).
Domain is all Real numbers except x = 5.
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Factor:
f(x) = [(x-5)(x+5)]/[2(x-5)]
Cancel the common (x-5) factors.
f(x) = (x+5)/2
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C%28x%2B5%29%2F2%29
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f(x) = (x+2) / (x^2-x-6).
Factor: (x+2)/[(x-3)(x+2)]
Domain is all Real numbers except x = -2
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Cancel the common (x+2) factors.
f(x) = 1/(x-3)
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C1%2F%28x-3%29%29
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Cheers,
Stan H.
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when I did, the instructor said i was wrong; see his response:
what did i do wrong