SOLUTION: trying to factor 2x^3+7x^2-3x-18 completely given that x+2 is a factor. Tried to factor the first 3 numbers and the last three but getting stuck and don't understand how x+2 fits
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Question 436722: trying to factor 2x^3+7x^2-3x-18 completely given that x+2 is a factor. Tried to factor the first 3 numbers and the last three but getting stuck and don't understand how x+2 fits in. Help! (and thanks!) Answer by scott8148(6628) (Show Source):
You can put this solution on YOUR website! using either long or synthetic division, dividing 2x^3+7x^2-3x-18 by x+2 gives ___ 2x^2 + 3x - 9
2x^2 + 3x - 9 factors to ___ (2x - 3)(x + 3)
so the factors of 2x^3+7x^2-3x-18 are ___ (x + 2)(2x - 3)(x + 3)
