SOLUTION: solve the quadratic equation (x-3)squared=36 by the square root method.

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Question 4356: solve the quadratic equation (x-3)squared=36 by the square root method.
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
+%28x-3%29+%5E2+=+36

Take the square root of both sides to "undo" the square.

sqrt+%28%28x-3%29%5E2%29+=+0+%2B-+sqrt%2836%29
+x+-+3+=+0+%2B-+6

To solve for x, add +3 to each side of the equation:
+x+-3+%2B+3+=+3+%2B-+6
x+=+3+%2B-+6
In the first case, this means x = 3 + 6, which is x = 9.
In the second case, this means x= 3 - 6, which is x = -3.

Check your answers in the original equation:
+%28x-3%29+%5E2+=+36
For x = 9, +%289-3%29+%5E2+=+36
For x = -3, +%28-3-3%29+%5E2+=+36

R^2 at SCC