SOLUTION: The profit that the vendor makes per day by selling x pretzels is given by the function P(x)=-0.002x(squared)+1.4x-150. Find the number of pretzels that must be sold to maximized p
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-> SOLUTION: The profit that the vendor makes per day by selling x pretzels is given by the function P(x)=-0.002x(squared)+1.4x-150. Find the number of pretzels that must be sold to maximized p
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Question 430209: The profit that the vendor makes per day by selling x pretzels is given by the function P(x)=-0.002x(squared)+1.4x-150. Find the number of pretzels that must be sold to maximized profit. Found 2 solutions by nerdybill, Sphinx pinastri:Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! P(x)=-0.002x^2+1.4x-150
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Since the coefficient associated with the x^2 term is negative, we know that it is a parabola that opens downwards. Therefore, the vertex is the maximum.
The value of x of the vertex can be found by:
x = -b/(2a)
x = -1.4/(2*(-0.002))
x = 1.4/0.004
x = 350 pretzels
You can put this solution on YOUR website! I wonder why the profit is negative when x is large?
Anyway, let's take the derivative:
Derivative is equal 0 at extrema.
