Question 4269: The perimeter of a rectangular floor is 42 feet, and the area is 108 square feet. Find the length of the floor. Answer by Earlsdon(6294) (Show Source):
You can put this solution on YOUR website! Assign the variables: Let x = the length of the side of the square.
Then x+6 = the length of the diagonal.
Apply the Pythagorean theorem: c^2 = a^2 + b^2 c is the diagonal, a and b are the sides of the square.
(x+6)^2 = x^2 + x^2
x^2 + 12x + 36 = 2x^2 Subtract x^2 from both sides.
12x + 36 = x^2 Rewrite in standard quadratic form.
x^2 - 12x - 36 = 0 Solve the quadratic using the quadratic formula.
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