Question 420735: 12x^2-18x-6
i used the -b +- square root of b^2-4ac over 2a formula, but i dont know if my answer is right. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 12x^2-18x-6
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= 6(2x^2-3x-1)
if you are factoring.
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12x^2-18x-6
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x = [18 +- sqrt(18^2-4*12*-6)]/24
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x = [18 +- sqrt(612)]/24
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x = [18 +- sqrt(36*17)]/24
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x = [18 +- 6*sqrt(17)]/24
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x = [3 +- sqrt(17)]/4
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Cheers,
Stan H.
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