SOLUTION: The length of a rectangle is 5 inches more than the width. The perimeter is 30 inches. Find the length and width. L =... inches w= ... inches Fill in the blank(...)

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The length of a rectangle is 5 inches more than the width. The perimeter is 30 inches. Find the length and width. L =... inches w= ... inches Fill in the blank(...)      Log On


   

Question 415873: The length of a rectangle is 5 inches more than the width. The perimeter is 30 inches. Find the length and width.
L =... inches
w= ... inches
Fill in the blank(...)
Found 2 solutions by ewatrrr, Mr.Math:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Let x and (x+5in) represent the width and length respectively

Question states***

  2(x+5in) + 2x = 30in

Solving for x

   4x = 20

    x = 5in, the width.  The length is 10in   (5in + 5in)

CHECKING our Answer***

 2*10in + 2*5in = 20in + 10in = 30in

Answer by Mr.Math(29) About Me  (Show Source):
You can put this solution on YOUR website!
Let the length of a rectangle is x, then the width is x-5.
The perimeter is 2%2A%28a+%2B+b%29+=+2%2A%28x+%2B+%28x+-+5%29%29+=+30.
Then:
2%2A%28x+%2B+x+-+5%29+=+30
2%2A%282x+-+5%29+=+30
4x+-+10+=+30
4x+=+40
x+=+10
x+-+5+=+5
Answer: the length of a rectangle is 10 inches and the width is 5 inches.