SOLUTION: Shelly is 5 years older than Michele. Four years ago the sum of their ages was 65. Find the age of each person now. Shelly is(fill in the answer) years Michele is (fill in the

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Shelly is 5 years older than Michele. Four years ago the sum of their ages was 65. Find the age of each person now. Shelly is(fill in the answer) years Michele is (fill in the       Log On


   

Question 415196: Shelly is 5 years older than Michele. Four years ago the sum of their ages was 65. Find the age of each person now.
Shelly is(fill in the answer) years
Michele is (fill in the answer) years.
Four years ago Now
Shelly x + 1 x + 5
Michele x - 4 x
The chart could probably help
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

let Shelly's age be x and Michele's age be y
given:
Shelly is 5 years older than Michele.
so, x=y%2B5
Four years ago the sum of their ages was 65
x%2By%2B4=65
x%2By=65-4
x%2By=61........replace x=y%2B5 and find y
y%2B5%2By=61
2y=61-5
2y=56
y=56%2F2
y=28.........now find x

x=y%2B5
x=28%2B5
x=+33

so, Shelly is 33 years old and Michele is 28 years old