SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function.
f(x)=-(x+3)^2-1
I have been having problems with these and can't seem to
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function.
f(x)=-(x+3)^2-1
I have been having problems with these and can't seem to
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Question 415015: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function.
f(x)=-(x+3)^2-1
I have been having problems with these and can't seem to get it right. Can someone help please! Answer by woolybear(13) (Show Source):
You can put this solution on YOUR website! f(x)=-(x+3)^(2)-1
Replace f(x) with y to find the properties of the parabola.
y=-(x+3)^(2)-1
This is the form of a paraboloa. Use this form to determine the values used to find vertex and x-y intercepts.
y=a(x-h)^(2)+k
Use the standard form to determine the vertex and x-y intercepts.
a=-1_k=-1_h=-3
The vertex of a parabola is (h,k).
Vertex: (-3,-1)
