SOLUTION: so the problem reads as 4^2 = 10v - 5 I've only ever been working with them in standard form. ax^2 + bx + c = 0 I'm stuck on what to do. What's a, b, & c? should I re-write the

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: so the problem reads as 4^2 = 10v - 5 I've only ever been working with them in standard form. ax^2 + bx + c = 0 I'm stuck on what to do. What's a, b, & c? should I re-write the       Log On


   

Question 412992: so the problem reads as 4^2 = 10v - 5
I've only ever been working with them in standard form. ax^2 + bx + c = 0
I'm stuck on what to do. What's a, b, & c? should I re-write the problem in standard form? if I do how do you do that?
Answer by jsmallt9(3759) About Me  (Show Source):
You can put this solution on YOUR website!
I assume the equation is:
4v%5E2+=+10v+-+5

And, yes, you do start by transforming the equation into standard form. To do this you can either:
  • Subtract 4v%5E2 from each side of the equation giving you:
    0+=+-4v%5E2+%2B+10v+-+5
    or
  • Subtract 10v and add 5 giving you:
    4v%5E2-10v%2B5+=+0

Both of these will work. Since having a minus in front of the squared term makes the rest of the problem a little harder, I prefer the second equation over the first.

With either equation the next step is to factor or to use the Quadratic Formula. Since you have already done problems in standard form, I'll leave the rest up to you.