SOLUTION: steve traveled 600 miles at a certain speed. had he gone 20mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: steve traveled 600 miles at a certain speed. had he gone 20mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle.      Log On


   



Question 40666This question is from textbook
: steve traveled 600 miles at a certain speed. had he gone 20mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle. This question is from textbook

Found 2 solutions by checkley71, stanbon:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
600/X=(600/X+20)-1 OR 600/X=(600-X-20)/(X+20) OR 600X-X~2-20X=600X-12,000 OR
-X~2-20X=-12,000 OR X~2+20X-12,000 OR (X-100)(X+120)=0 OR X=100 MPH
THEN X+20=120 MPH
PROOX 600/100=6 HOURS & 600/120=5 HOURS 6-5=1 HOUR LESS @ 120 MPH.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
steve traveled 600 miles at a certain speed. had he gone 20mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle.
1st trip Data:
distance = 600 miles; Rate= x mph; Time= 600/x hrs.
2nd trip Data:
Distance=600 miles;Rate=(x+20)mph; Time=600/(x+20)
EQUATION:
1st trip time = 2nd trip time +1 hr.
600/x = 600/(x+20) + 1
600(x+20)=600x+x(x+20)
600x+12000=600x+x^2+20x
x^2+20x-12000=0
(x+120)(x-100)=0
x=100 mph (Speed of Steve's vehicle on the 1st trip)
Cheers,
Stan H.