SOLUTION: How do you solve 3(x+7/3)^2=1 i've tried to do it but i just cant figure it out my teacher did not teach me how do to a question like his. Please help, Thank you!

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: How do you solve 3(x+7/3)^2=1 i've tried to do it but i just cant figure it out my teacher did not teach me how do to a question like his. Please help, Thank you!      Log On


   

Question 398558: How do you solve 3(x+7/3)^2=1 i've tried to do it but i just cant figure it out my teacher did not teach me how do to a question like his. Please help, Thank you!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
3%28x%2B7%2F3%29%5E2=1 Start with the given equation.


%28x%2B7%2F3%29%5E2=%281%29%2F%283%29 Divide both sides by 3.


x%2B7%2F3=%22%22%2B-sqrt%281%2F3%29 Take the square root of both sides.


x%2B7%2F3=sqrt%281%2F3%29 or x%2B7%2F3=-sqrt%281%2F3%29 Break up the "plus/minus" to form two equations.


x%2B7%2F3=sqrt%283%29%2F3 or x%2B7%2F3=-sqrt%283%29%2F3 Simplify the square root.


x=-7%2F3%2Bsqrt%283%29%2F3 or x=-7%2F3-sqrt%283%29%2F3 Subtract 7%2F3 from both sides.


x=%28-7%2Bsqrt%283%29%29%2F%283%29 or x=%28-7-sqrt%283%29%29%2F%283%29 Combine the fractions.


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Answer:


So the solutions are x=%28-7%2Bsqrt%283%29%29%2F%283%29 or x=%28-7-sqrt%283%29%29%2F%283%29.


If you need more help, email me at jim_thompson5910@hotmail.com

Also, feel free to check out my tutoring website

Jim