# SOLUTION: How would you solve this? m4 +13m2 &#8722; 48 = 0 would you separate the equation out so it's m2(m2+13)-48=0?

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: How would you solve this? m4 +13m2 &#8722; 48 = 0 would you separate the equation out so it's m2(m2+13)-48=0?      Log On

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 Click here to see ALL problems on Quadratic Equations Question 396120: How would you solve this? m4 +13m2 − 48 = 0 would you separate the equation out so it's m2(m2+13)-48=0?Answer by Alan3354(31519)   (Show Source): You can put this solution on YOUR website!Assuming the 4 and 2 are exponents, Sub x for m^2 (x+16)(x-3) = 0 x = 3, -16 ---------- Sub back m = ± sqrt(3) ------------ m = ± 4i ================ You might factor that, too. Same answers, simpler, but if factoring isn't possible, substitution always works.