SOLUTION: find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function. f(x)= -5(5+3)^2 + 8 the vertex is (type an ordered pair)

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function. f(x)= -5(5+3)^2 + 8 the vertex is (type an ordered pair)       Log On


   

Question 395555: find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function.
f(x)= -5(5+3)^2 + 8
the vertex is (type an ordered pair)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

f(x)= -5(x+3)^2 + 8 |adjusted for typo on the 'x'

Finding vertex

Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

f(x)= -5(x+3)^2 + 8  | Vertex is Pt(-3,8) Line of symmetry is x= -3

 -5 = a < 0, parabola opens downward f(-3) = 8 is a maximum point for f(x)