SOLUTION: My question is a quadratic equation: 8x+27=5x. I tried to solve by subtracting 8x by 5x. the 3x +27=0. I subtracted 27 and got 3x= -27. After that I got 3x= -27. My answer was x= -

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: My question is a quadratic equation: 8x+27=5x. I tried to solve by subtracting 8x by 5x. the 3x +27=0. I subtracted 27 and got 3x= -27. After that I got 3x= -27. My answer was x= -      Log On


   

Question 390387: My question is a quadratic equation: 8x+27=5x. I tried to solve by subtracting 8x by 5x. the 3x +27=0. I subtracted 27 and got 3x= -27. After that I got 3x= -27. My answer was x= -9. I am unsure whether this is the right method or if this is right?
My name is Joe. I'm in the 9th grade/Geometry Honors
Found 2 solutions by richard1234, stanbon:
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
It's correct. However the equation is not quadratic, since the degree is 1. It is definitely solvable by the quadratic formula (letting a = 0); it'd be kind of pointless using it though :)

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
My question is a quadratic equation: 8x+27=5x. I tried to solve by subtracting 8x by 5x. the 3x +27=0. I subtracted 27 and got 3x= -27. After that I got 3x= -27. My answer was x= -9. I am unsure whether this is the right method or if this is right?
My name is Joe. I'm in the 9th grade/Geometry Honors
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Hi Joe---
x = -9 is correct.
Cheers,
Stan H.
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