SOLUTION: how do you factor 3x^2-4x+7?

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Question 388366: how do you factor 3x^2-4x+7?
Found 2 solutions by Edwin McCravy, checkley79:
Answer by Edwin McCravy(20056) (Show Source):
You can put this solution on YOUR website!

how do you factor 3x^2-4x+7

Multiply 3 by 7, getting 21 Think of all the ways to factor 21 using integers: 21 x 1 = 21 7 x 3 = 21 Since the 7 is positive, list their sums 21 + 1 = 22 7 + 3 = 10 Since the middle coefficient in absolute value, 4 is not listed then the trinomial doesn't factor. So the trinomial is prime. Edwin

Answer by checkley79(3341) (Show Source):
You can put this solution on YOUR website!
3x^2-4x+7
Using the following quadratic equation
{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
x=(4+-sqrt[-4^2-4*3*7])/2*3
x=(4+-sqrt[16-84])/6
x=(4+-sqrt-68)/6
x=(4+-8.246i)/6
x=4/6+-8.246i
x=.666+-1.374i ans.