You can put this solution on YOUR website! Determine the nature of solution
y^2= 3/4y + 4/5
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y^2-(3/4)y-(4/5) = 0
Multiply thru by 20 to get:
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20y^2-15y-16 = 0
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b^2-4ac = 15^2-4*20*-16 > 0
so there are two unequal Real
Number solutions.
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Cheers,
Stan H.