SOLUTION: Hi Please help.
Partial differentiate the following, the d's are the 'curly' d's but couldnt get them on here Find df/dx, df/dy, d^2f=dx^2 and d^2f/dy^2 for f(x, y) = e^(x+y).s
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-> SOLUTION: Hi Please help.
Partial differentiate the following, the d's are the 'curly' d's but couldnt get them on here Find df/dx, df/dy, d^2f=dx^2 and d^2f/dy^2 for f(x, y) = e^(x+y).s
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Question 384886: Hi Please help.
Partial differentiate the following, the d's are the 'curly' d's but couldnt get them on here Find df/dx, df/dy, d^2f=dx^2 and d^2f/dy^2 for f(x, y) = e^(x+y).sin(x - y).
Thank You Answer by richard1234(7193) (Show Source):
You can put this solution on YOUR website! To find df/dx and df/dy, just assume that y and x are constants respectively (I'm also using d = differential). So,
(by the Product Rule)
Do the same for df/dy. Then you can find the second derivatives by taking the derivative of df/dx, df/dy.
