SOLUTION: Hello, My instructions were to "Graph the quadratic function. Label the vertex and axis of symmetry. " However, i dont understand this problem: {{{ y=2x^2 -12x }}} I t

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Hello, My instructions were to "Graph the quadratic function. Label the vertex and axis of symmetry. " However, i dont understand this problem: {{{ y=2x^2 -12x }}} I t      Log On


   

Question 382523: Hello,
My instructions were to "Graph the quadratic function. Label the vertex and axis of symmetry. "
However, i dont understand this problem:
+y=2x%5E2+-12x+
I tried using the -b/2a formula , and i got the answer 3.
Then i made a t-chart, to get other points to make my parabola, but the numbers were very off, (one of my 'y' coordinates came out to 32) . I dont think i did it right, and im not good at algebra what so ever, so i am absolutely positive i got it all wrong.
Thank you in advance,
Jackie
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
it looks like you're doing fine

you found the axis of symmetry (x = 3) ; and when x=-2 , y=32

the vertex is on the axis of symmetry - just find the value of y


FYI ___ the roots (x-intercepts) are 0 and 6