SOLUTION: what are the x-intercepts (to the nearest tenth) of the equation f(x)=-2x^2+4x+3

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Question 378185: what are the x-intercepts (to the nearest tenth) of the equation f(x)=-2x^2+4x+3
Answer by ewatrrr(24785) About Me  (Show Source):
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Hi

 x-intercepts (to the nearest tenth) of the equation f(x)=-2x^2+4x+3

0 = -2x^2 + 4x + 3

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

x+=+%28-4+%2B-+sqrt%28+40+%29%29%2F%28-4%29+

x+=+%28-4+%2B-+sqrt%28+4%2A10+%29%29%2F%28-4%29+

x+=+%28-4+%2B-+2%2Asqrt%2810+%29%29%2F%28-4%29+

x+=+1+%2B-+%28-.5sqrt%2810%29%29

x = 1 - 1.58 = -.58 = -.6

x = 1 + 1.58 = 2.58  = 2.6

x- Intercepts: Pt(-.6,0) and Pt(2.6,0)

graph%28+300%2C+300%2C-6%2C6%2C-6%2C6%2C-2x%5E2+%2B+4x+%2B+3%0D%0A%29+