SOLUTION: Hi can somebody please help with the below, and be as kind as to talk me through the steps, i am totally confused with this. Find dy/dx as a function of x and y when: i) x^2y^3

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Hi can somebody please help with the below, and be as kind as to talk me through the steps, i am totally confused with this. Find dy/dx as a function of x and y when: i) x^2y^3      Log On


   

Question 376206: Hi can somebody please help with the below, and be as kind as to talk me through the steps, i am totally confused with this.
Find dy/dx as a function of x and y when:
i) x^2y^3 - x^2 + 3y - 3 = 0
ii)(1 - x^2) tan^-1 y = 3
Really appreciate this.
Thanks
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
i) 2xy%5E3+%2B+x%5E2%2A3y%5E2%28dy%2Fdx%29+-+2x+%2B+3%28dy%2Fdx%29+=+0,
%283x%5E2y%5E2+%2B+3%29%28dy%2Fdx%29+=+2x+-+2xy%5E3,
dy%2Fdx+=+%282x%281-y%5E3%29%29%2F%283%281%2Bx%5E2y%5E2%29%29.
ii)%28-2x%29%2A%28arctan+y%29%2B%281-x%5E2%29%2A%28%28dy%2Fdx%29%2F%281%2By%5E2%29%29+=+0,
dy%2Fdx++=+%282x%2A%28arctan+y%29%281%2By%5E2%29%29%2F%281-x%5E2%29