Question 371786: A model rocket is launched straight up from a platform. The height of the rocket is given by h(t)=-16t^2+266t+10
a. What is the altitude of the rocket 2 seconds after launching?
b. How high does the rocket go? Answer by scott8148(6628) (Show Source):
b. the max value for h is the vertex of the parabola, which lies on the axis of symmetry
___ the general equation for the axis of symmetry is ___ x = -b / (2a)
___ in this case ___ t = -266 / [2(-16)] ___ plug in this value of t to find the max height