Question 37169This question is from textbook Algebra 1
: Factor. Check by using FOIL or the distributive property.
m^3 + 6m^2 + 9m
and then a question not from the book, b^2-6b-10, factor this one also please.
This question is from textbook Algebra 1
Found 2 solutions by josmiceli, jcmtnez:
Answer by josmiceli(19441)   (Show Source):
Answer by jcmtnez(53)  (Show Source):
You can put this solution on YOUR website! (1) Here is the first
m^3+6m^2+9m=0 , This polynomial of degree 3 is divisible by m, therefore we divede by m and get:
m(m^2+6m+9)=0 Now we have to solve the polynomial of degree two, and the solution is m=-3, and is unique. Finally we get
m(m+3)(m+3) As the factorization of m^3 + 6m^2 + 9m
(2) Here is the second
b^2-6b-10=0, First have to solve the equation, find the roots, we can do this using the general formula or using more advance methods. Using the formula we get as a result b=3+sqrt(19), and b=3-sqrt(19). Then the factors will be
(b-(3-sqrt(19))(b-(3+(sqrt(19))
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