SOLUTION: find the vertex, axis of symmetry, and the maximum value or minimum value {{{ f(x)=(x-1)^2+2 }}}

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: find the vertex, axis of symmetry, and the maximum value or minimum value {{{ f(x)=(x-1)^2+2 }}}      Log On


   

Question 367782: find the vertex, axis of symmetry, and the maximum value or minimum value
+f%28x%29=%28x-1%29%5E2%2B2+
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,

*Note: vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

+f%28x%29=%28x-1%29%5E2%2B2+vertex is (1,2) which is a minimum as 'a' = 1 (a >0 parabola opens upward)



graph%28+300%2C+300%2C-6%2C6%2C-6%2C6%2C%28x-1%29%5E2+%2B+2%29+