SOLUTION: durin the first part of a trip a canoesit travels 64 miles at a certain speed. The conoeist treavels 22 miles on the secondo part of the trip at a speed of 5 mph slower. the total
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-> SOLUTION: durin the first part of a trip a canoesit travels 64 miles at a certain speed. The conoeist treavels 22 miles on the secondo part of the trip at a speed of 5 mph slower. the total
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Question 366992: durin the first part of a trip a canoesit travels 64 miles at a certain speed. The conoeist treavels 22 miles on the secondo part of the trip at a speed of 5 mph slower. the total time for the trip is 4 hours what was the speed of each part of the trip. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! durin the first part of a trip a canoesit travels 64 miles at a certain speed. The conoeist treavels 22 miles on the secondo part of the trip at a speed of 5 mph slower. the total time for the trip is 4 hours what was the speed of each part of the trip.
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let speed be x mph during the first part
distance = 64 miles
time taken = 64/x
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second part
speed = x-5
distance = 22 miles.
time = 22/(x-5)
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time first leg + time second leg = total time
64/x+22/(x-5)=4
64(x-5)+22x/ x(x-5)=4
64x-320+22x= 4x(x-5)
86x-320=4x^2-20x
4x^2-86x-20x+320=0
4x^2-106x+320=0
/2
2x^2-53x+160=0
quadratic equation to find the roots.
discriminant = 1529
x1= (53+sqrt(1529))/4
x1=23.02
x2=(53-sqrt(1529))/4
x2= 3.47 ( not possible)
first leg speed = 23mph
second leg = 18 mph
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m.ananth@hotmail.ca
