SOLUTION: Step by step Original- ax^2 + bx + c =0 1. subtract c from each side 2. Divide each side by a 3. Add he square of half the coefficient of x to each side 4.write the left s

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Step by step Original- ax^2 + bx + c =0 1. subtract c from each side 2. Divide each side by a 3. Add he square of half the coefficient of x to each side 4.write the left s      Log On


   



Question 36454: Step by step
Original- ax^2 + bx + c =0
1. subtract c from each side
2. Divide each side by a
3. Add he square of half the coefficient of x to each side
4.write the left side as a perfect square
5.use a common denominator to express the right side as a single fraction
6. find the square root of eac side
7. solve for x by subtracting the same term form each side
8. use a common denominator to express the right side as a single fraction
once all the steps are done you should end up with the quadratice formula but i cant get past step three and i need each step. PLEASE HELp

Answer by atif.muhammad(135) About Me  (Show Source):
You can put this solution on YOUR website!
Original- ax^2 + bx + c =0 
1. subtract c from each side

ax^2 + bx = -c

2. Divide each side by a

x^2 + (b/a)x = -c/a
3. Add he square of half the coefficient of x to each side

x^2 + (b/a)x + (b/2a)^2 = -c/a + (b/2a)^2

x^2 + (b/a)x + (b^2/4a^2) = -c/a + (b^2/4a^2)

4.write the left side as a perfect square

(x+ b/2a)^2 = -c/a + (b^2/4a^2)

5.use a common denominator to express the right side as a single fraction

(x+ b/2a)^2 = (-4ac + b^2)/(4a^2)

6. find the square root of eac side 

(x+ b/2a)^2 = (b^2 - 4ac)/(4a^2)

(x+ b/2a) = %2B-+sqrt%28b%5E2-4ac%29%2F2a

7. solve for x by subtracting the same term form each side

(x+ b/2a) = %2B-+sqrt%28b%5E2-4ac%29%2F2a

x = +-b%2F2a+%28%2B-+sqrt%28b%5E2-4ac%29%2F2a%29
8. use a common denominator to express the right side as a single fraction 

x = +%28%28-b%2B-+sqrt%28b%5E2-4ac%29%29%2F2a%29