SOLUTION: This problem is in my college algebra for calculus class under quadratic equations. The book gives the answer but not how it is worked out. Can you please help. It says to solve 3y
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-> SOLUTION: This problem is in my college algebra for calculus class under quadratic equations. The book gives the answer but not how it is worked out. Can you please help. It says to solve 3y
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Question 363607: This problem is in my college algebra for calculus class under quadratic equations. The book gives the answer but not how it is worked out. Can you please help. It says to solve 3y^3-5y^2-2y=0 Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! 3y^3-5y^2-2y=0
y(3y^2-5y-2)=0
y(3y^2-6y+y-2)=0 Factoring by grouping.
y(3y(y-2)+(y-2))=0
y(3y+1)(y-2)=0
y=0, y=-1/3, y=2
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Ed
