SOLUTION: f(x)=x^2-x-2/x^2-16 Looking to find the x-int

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: f(x)=x^2-x-2/x^2-16 Looking to find the x-int      Log On


   



Question 360232: f(x)=x^2-x-2/x^2-16 Looking to find the x-int
Answer by neatmath(302) About Me  (Show Source):
You can put this solution on YOUR website!
If this is the problem:

f%28x%29=%28x%5E2-x-2%29%2F%28x%5E2-16%29 then proceed as such:

If you need to find the x-intercept(s), you are looking for the point where y=0

When y=0, you know that the point will definitely be on the x-axis, and you will end up with a point (x,0)

So, we just need to find the point where the function equals 0!

0=%28x%5E2-x-2%29%2F%28x%5E2-16%29

We know that the denominator can NEVER equal 0, so we can just remove the denominator, and set the numerator equal to 0. So,

0=%28x%5E2-x-2%29

Then we just need to factor this remaining polynomial if possible.

0=%28x-2%29%28x%2B1%29

So since we know the 2 factors when multiplied equal 0, we know that either the first factor must equal 0, or the 2nd factor must equal 0.

So we have

x-2=0 or x%2B1=0

x=2 or x=-1

Therefore the x-intercepts are 2 and -1 or

the x-intercepts are the points (2,0) and (-1,0)

I hope this helps!