SOLUTION: please help me, very lost Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function. f(x) = 1/5(x+8)^2+2 1) The vertex is

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: please help me, very lost Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function. f(x) = 1/5(x+8)^2+2 1) The vertex is       Log On


   

Question 359576: please help me, very lost

Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function.

f(x) = 1/5(x+8)^2+2

1) The vertex is "ordered pair" ??
2) The line of symmetry is x = ??
3) What is the maximum/minimum value of f(x) ??
4) Is the value, f(-8) = 2 a minimum or maximum ??
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Don't be lost, study the "vertex form".
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The equation is already in vertex form, y=a%28x-h%29%5E2%2Bk where (h,k) is the vertex.
1) Comparing, (h,k)=(-8,2)
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2) The vertex lies on the axis of symmetry, x=-8
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3) Since a=1%2F5 and a%3E0, then the parabola opens upwards and the value at the vertex (k) is a minimum.
f%5Bmin%5D=2
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4) From 3), it's a minimum.
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