SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function.
{{{ f(x) = 1/5(x+8)^2+2 }}}
1) The vertex is ???
2) The line of symm
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function.
{{{ f(x) = 1/5(x+8)^2+2 }}}
1) The vertex is ???
2) The line of symm
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Question 358712: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function.
1) The vertex is ???
2) The line of symmetry is x= ??
3) What is the maximum/minimum value of f(x)
4) Is the value f (-8)=2, a minimum or maximum??
Could someone please help me and please show me what the graph looks like
The way you rendered your function, the questions asked don't make any sense. Hence, I'm going to presume that you really meant:
instead of what you actually wrote which was:
Your function is in vertex form, , which has a vertex at , an axis of symmetry at , a minimum or maximum value equal to the function value at the vertex, and the vertex is a maximum when or a minimum when
Hint: Re-write your function thusly:
John
My calculator said it, I believe it, that settles it
