SOLUTION: A man deposited $2000 in a savings bank paying him a certain interest. At the end of the year he withdraw $150. At the end of the second year the amount dew to him was $1947.50. Wh

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: A man deposited $2000 in a savings bank paying him a certain interest. At the end of the year he withdraw $150. At the end of the second year the amount dew to him was $1947.50. Wh      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 353827: A man deposited $2000 in a savings bank paying him a certain interest. At the end of the year he withdraw $150. At the end of the second year the amount dew to him was $1947.50. What was the rate of interest?
Answer by mananth(12270) About Me  (Show Source):
You can put this solution on YOUR website!
$ 2000 in savings bank
Let x% be the interest.
..
interest obtained = 20x.
he withdrew $150
Balance in account after 1 year = 2000-150+20x = 1850+20x
...
Interest for second year = 0.01x(1850+20x)+1850+20x = 1947.50
18.50x+0.2x^2+1850+20x=1947.50
0.2x^2+38.50x=1947.50-1850
0.2x^2+38.5x=97.5
multiply by 10
2x^2+385x-975 =0
discriminant = 156025
solve by quadratic formula
x1= 2.5%
x2= -195 ignore negative value
....
m.ananth@hotmail.ca